Optimal. Leaf size=346 \[ -\frac {b^2 n^2 x^{1-m} (f x)^{-1+m}}{3 d^2 e m^3 \left (d+e x^m\right )}-\frac {b^2 n^2 x^{1-m} (f x)^{-1+m} \log (x)}{3 d^3 e m^2}+\frac {b n x^{1-m} (f x)^{-1+m} \left (a+b \log \left (c x^n\right )\right )}{3 d e m^2 \left (d+e x^m\right )^2}-\frac {2 b n x (f x)^{-1+m} \left (a+b \log \left (c x^n\right )\right )}{3 d^3 m^2 \left (d+e x^m\right )}-\frac {x^{1-m} (f x)^{-1+m} \left (a+b \log \left (c x^n\right )\right )^2}{3 e m \left (d+e x^m\right )^3}-\frac {2 b n x^{1-m} (f x)^{-1+m} \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac {d x^{-m}}{e}\right )}{3 d^3 e m^2}+\frac {b^2 n^2 x^{1-m} (f x)^{-1+m} \log \left (d+e x^m\right )}{d^3 e m^3}+\frac {2 b^2 n^2 x^{1-m} (f x)^{-1+m} \text {Li}_2\left (-\frac {d x^{-m}}{e}\right )}{3 d^3 e m^3} \]
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Rubi [A]
time = 0.47, antiderivative size = 346, normalized size of antiderivative = 1.00, number of steps
used = 12, number of rules used = 9, integrand size = 29, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.310, Rules used = {2377, 2376,
2391, 2379, 2438, 2373, 266, 272, 46} \begin {gather*} \frac {2 b^2 n^2 x^{1-m} (f x)^{m-1} \text {PolyLog}\left (2,-\frac {d x^{-m}}{e}\right )}{3 d^3 e m^3}-\frac {2 b n x^{1-m} (f x)^{m-1} \log \left (\frac {d x^{-m}}{e}+1\right ) \left (a+b \log \left (c x^n\right )\right )}{3 d^3 e m^2}-\frac {2 b n x (f x)^{m-1} \left (a+b \log \left (c x^n\right )\right )}{3 d^3 m^2 \left (d+e x^m\right )}+\frac {b n x^{1-m} (f x)^{m-1} \left (a+b \log \left (c x^n\right )\right )}{3 d e m^2 \left (d+e x^m\right )^2}-\frac {x^{1-m} (f x)^{m-1} \left (a+b \log \left (c x^n\right )\right )^2}{3 e m \left (d+e x^m\right )^3}+\frac {b^2 n^2 x^{1-m} (f x)^{m-1} \log \left (d+e x^m\right )}{d^3 e m^3}-\frac {b^2 n^2 x^{1-m} \log (x) (f x)^{m-1}}{3 d^3 e m^2}-\frac {b^2 n^2 x^{1-m} (f x)^{m-1}}{3 d^2 e m^3 \left (d+e x^m\right )} \end {gather*}
Antiderivative was successfully verified.
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Rule 46
Rule 266
Rule 272
Rule 2373
Rule 2376
Rule 2377
Rule 2379
Rule 2391
Rule 2438
Rubi steps
\begin {align*} \int \frac {(f x)^{-1+m} \left (a+b \log \left (c x^n\right )\right )^2}{\left (d+e x^m\right )^4} \, dx &=\left (x^{1-m} (f x)^{-1+m}\right ) \int \frac {x^{-1+m} \left (a+b \log \left (c x^n\right )\right )^2}{\left (d+e x^m\right )^4} \, dx\\ &=-\frac {x^{1-m} (f x)^{-1+m} \left (a+b \log \left (c x^n\right )\right )^2}{3 e m \left (d+e x^m\right )^3}+\frac {\left (2 b n x^{1-m} (f x)^{-1+m}\right ) \int \frac {a+b \log \left (c x^n\right )}{x \left (d+e x^m\right )^3} \, dx}{3 e m}\\ &=-\frac {x^{1-m} (f x)^{-1+m} \left (a+b \log \left (c x^n\right )\right )^2}{3 e m \left (d+e x^m\right )^3}-\frac {\left (2 b n x^{1-m} (f x)^{-1+m}\right ) \int \frac {x^{-1+m} \left (a+b \log \left (c x^n\right )\right )}{\left (d+e x^m\right )^3} \, dx}{3 d m}+\frac {\left (2 b n x^{1-m} (f x)^{-1+m}\right ) \int \frac {a+b \log \left (c x^n\right )}{x \left (d+e x^m\right )^2} \, dx}{3 d e m}\\ &=\frac {b n x^{1-m} (f x)^{-1+m} \left (a+b \log \left (c x^n\right )\right )}{3 d e m^2 \left (d+e x^m\right )^2}-\frac {x^{1-m} (f x)^{-1+m} \left (a+b \log \left (c x^n\right )\right )^2}{3 e m \left (d+e x^m\right )^3}-\frac {\left (2 b n x^{1-m} (f x)^{-1+m}\right ) \int \frac {x^{-1+m} \left (a+b \log \left (c x^n\right )\right )}{\left (d+e x^m\right )^2} \, dx}{3 d^2 m}+\frac {\left (2 b n x^{1-m} (f x)^{-1+m}\right ) \int \frac {a+b \log \left (c x^n\right )}{x \left (d+e x^m\right )} \, dx}{3 d^2 e m}-\frac {\left (b^2 n^2 x^{1-m} (f x)^{-1+m}\right ) \int \frac {1}{x \left (d+e x^m\right )^2} \, dx}{3 d e m^2}\\ &=\frac {b n x^{1-m} (f x)^{-1+m} \left (a+b \log \left (c x^n\right )\right )}{3 d e m^2 \left (d+e x^m\right )^2}-\frac {2 b n x (f x)^{-1+m} \left (a+b \log \left (c x^n\right )\right )}{3 d^3 m^2 \left (d+e x^m\right )}-\frac {x^{1-m} (f x)^{-1+m} \left (a+b \log \left (c x^n\right )\right )^2}{3 e m \left (d+e x^m\right )^3}-\frac {2 b n x^{1-m} (f x)^{-1+m} \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac {d x^{-m}}{e}\right )}{3 d^3 e m^2}-\frac {\left (b^2 n^2 x^{1-m} (f x)^{-1+m}\right ) \text {Subst}\left (\int \frac {1}{x (d+e x)^2} \, dx,x,x^m\right )}{3 d e m^3}+\frac {\left (2 b^2 n^2 x^{1-m} (f x)^{-1+m}\right ) \int \frac {x^{-1+m}}{d+e x^m} \, dx}{3 d^3 m^2}+\frac {\left (2 b^2 n^2 x^{1-m} (f x)^{-1+m}\right ) \int \frac {\log \left (1+\frac {d x^{-m}}{e}\right )}{x} \, dx}{3 d^3 e m^2}\\ &=\frac {b n x^{1-m} (f x)^{-1+m} \left (a+b \log \left (c x^n\right )\right )}{3 d e m^2 \left (d+e x^m\right )^2}-\frac {2 b n x (f x)^{-1+m} \left (a+b \log \left (c x^n\right )\right )}{3 d^3 m^2 \left (d+e x^m\right )}-\frac {x^{1-m} (f x)^{-1+m} \left (a+b \log \left (c x^n\right )\right )^2}{3 e m \left (d+e x^m\right )^3}-\frac {2 b n x^{1-m} (f x)^{-1+m} \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac {d x^{-m}}{e}\right )}{3 d^3 e m^2}+\frac {2 b^2 n^2 x^{1-m} (f x)^{-1+m} \log \left (d+e x^m\right )}{3 d^3 e m^3}+\frac {2 b^2 n^2 x^{1-m} (f x)^{-1+m} \text {Li}_2\left (-\frac {d x^{-m}}{e}\right )}{3 d^3 e m^3}-\frac {\left (b^2 n^2 x^{1-m} (f x)^{-1+m}\right ) \text {Subst}\left (\int \left (\frac {1}{d^2 x}-\frac {e}{d (d+e x)^2}-\frac {e}{d^2 (d+e x)}\right ) \, dx,x,x^m\right )}{3 d e m^3}\\ &=-\frac {b^2 n^2 x^{1-m} (f x)^{-1+m}}{3 d^2 e m^3 \left (d+e x^m\right )}-\frac {b^2 n^2 x^{1-m} (f x)^{-1+m} \log (x)}{3 d^3 e m^2}+\frac {b n x^{1-m} (f x)^{-1+m} \left (a+b \log \left (c x^n\right )\right )}{3 d e m^2 \left (d+e x^m\right )^2}-\frac {2 b n x (f x)^{-1+m} \left (a+b \log \left (c x^n\right )\right )}{3 d^3 m^2 \left (d+e x^m\right )}-\frac {x^{1-m} (f x)^{-1+m} \left (a+b \log \left (c x^n\right )\right )^2}{3 e m \left (d+e x^m\right )^3}-\frac {2 b n x^{1-m} (f x)^{-1+m} \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac {d x^{-m}}{e}\right )}{3 d^3 e m^2}+\frac {b^2 n^2 x^{1-m} (f x)^{-1+m} \log \left (d+e x^m\right )}{d^3 e m^3}+\frac {2 b^2 n^2 x^{1-m} (f x)^{-1+m} \text {Li}_2\left (-\frac {d x^{-m}}{e}\right )}{3 d^3 e m^3}\\ \end {align*}
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Mathematica [A]
time = 0.33, size = 240, normalized size = 0.69 \begin {gather*} \frac {x^{-m} (f x)^m \left (\frac {b m n \left (a+b \log \left (c x^n\right )\right )}{d \left (d+e x^m\right )^2}-\frac {m^2 \left (a+b \log \left (c x^n\right )\right )^2}{\left (d+e x^m\right )^3}+\frac {b n \left (2 a m-b n+2 b m \log \left (c x^n\right )\right )}{d^2 \left (d+e x^m\right )}-\frac {2 a b m n \log \left (d-d x^m\right )}{d^3}+\frac {3 b^2 n^2 \log \left (d-d x^m\right )}{d^3}+\frac {2 b^2 m n \left (n \log (x)-\log \left (c x^n\right )\right ) \log \left (d-d x^m\right )}{d^3}+\frac {2 b^2 n^2 \left (\frac {1}{2} m^2 \log ^2(x)+\left (-m \log (x)+\log \left (-\frac {e x^m}{d}\right )\right ) \log \left (d+e x^m\right )+\text {Li}_2\left (1+\frac {e x^m}{d}\right )\right )}{d^3}\right )}{3 e f m^3} \end {gather*}
Warning: Unable to verify antiderivative.
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Maple [F]
time = 0.06, size = 0, normalized size = 0.00 \[\int \frac {\left (f x \right )^{-1+m} \left (a +b \ln \left (c \,x^{n}\right )\right )^{2}}{\left (d +e \,x^{m}\right )^{4}}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 802 vs.
\(2 (327) = 654\).
time = 0.38, size = 802, normalized size = 2.32 \begin {gather*} \frac {{\left (b^{2} m^{2} n^{2} e^{3} \log \left (x\right )^{2} + {\left (2 \, b^{2} m^{2} n e^{3} \log \left (c\right ) + {\left (2 \, a b m^{2} n - 3 \, b^{2} m n^{2}\right )} e^{3}\right )} \log \left (x\right )\right )} f^{m - 1} x^{3 \, m} + {\left (3 \, b^{2} d m^{2} n^{2} e^{2} \log \left (x\right )^{2} + 2 \, b^{2} d m n e^{2} \log \left (c\right ) + {\left (2 \, a b d m n - b^{2} d n^{2}\right )} e^{2} + {\left (6 \, b^{2} d m^{2} n e^{2} \log \left (c\right ) + {\left (6 \, a b d m^{2} n - 7 \, b^{2} d m n^{2}\right )} e^{2}\right )} \log \left (x\right )\right )} f^{m - 1} x^{2 \, m} + {\left (3 \, b^{2} d^{2} m^{2} n^{2} e \log \left (x\right )^{2} + 5 \, b^{2} d^{2} m n e \log \left (c\right ) + {\left (5 \, a b d^{2} m n - 2 \, b^{2} d^{2} n^{2}\right )} e + 2 \, {\left (3 \, b^{2} d^{2} m^{2} n e \log \left (c\right ) + {\left (3 \, a b d^{2} m^{2} n - 2 \, b^{2} d^{2} m n^{2}\right )} e\right )} \log \left (x\right )\right )} f^{m - 1} x^{m} - {\left (b^{2} d^{3} m^{2} \log \left (c\right )^{2} + a^{2} d^{3} m^{2} - 3 \, a b d^{3} m n + b^{2} d^{3} n^{2} + {\left (2 \, a b d^{3} m^{2} - 3 \, b^{2} d^{3} m n\right )} \log \left (c\right )\right )} f^{m - 1} - 2 \, {\left (3 \, b^{2} d^{2} f^{m - 1} n^{2} x^{m} e + b^{2} d^{3} f^{m - 1} n^{2} + 3 \, b^{2} d f^{m - 1} n^{2} x^{2 \, m} e^{2} + b^{2} f^{m - 1} n^{2} x^{3 \, m} e^{3}\right )} {\rm Li}_2\left (-\frac {x^{m} e + d}{d} + 1\right ) - {\left ({\left (2 \, b^{2} m n e^{3} \log \left (c\right ) + {\left (2 \, a b m n - 3 \, b^{2} n^{2}\right )} e^{3}\right )} f^{m - 1} x^{3 \, m} + 3 \, {\left (2 \, b^{2} d m n e^{2} \log \left (c\right ) + {\left (2 \, a b d m n - 3 \, b^{2} d n^{2}\right )} e^{2}\right )} f^{m - 1} x^{2 \, m} + 3 \, {\left (2 \, b^{2} d^{2} m n e \log \left (c\right ) + {\left (2 \, a b d^{2} m n - 3 \, b^{2} d^{2} n^{2}\right )} e\right )} f^{m - 1} x^{m} + {\left (2 \, b^{2} d^{3} m n \log \left (c\right ) + 2 \, a b d^{3} m n - 3 \, b^{2} d^{3} n^{2}\right )} f^{m - 1}\right )} \log \left (x^{m} e + d\right ) - 2 \, {\left (3 \, b^{2} d^{2} f^{m - 1} m n^{2} x^{m} e \log \left (x\right ) + b^{2} d^{3} f^{m - 1} m n^{2} \log \left (x\right ) + 3 \, b^{2} d f^{m - 1} m n^{2} x^{2 \, m} e^{2} \log \left (x\right ) + b^{2} f^{m - 1} m n^{2} x^{3 \, m} e^{3} \log \left (x\right )\right )} \log \left (\frac {x^{m} e + d}{d}\right )}{3 \, {\left (3 \, d^{5} m^{3} x^{m} e^{2} + d^{6} m^{3} e + 3 \, d^{4} m^{3} x^{2 \, m} e^{3} + d^{3} m^{3} x^{3 \, m} e^{4}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {{\left (f\,x\right )}^{m-1}\,{\left (a+b\,\ln \left (c\,x^n\right )\right )}^2}{{\left (d+e\,x^m\right )}^4} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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